Q. 8.3TI - Intermediate Algebra

Question

Simplify: $\left(a\right) \sqrt{-169}$    $\left(b\right)-\sqrt{81}$

Step-by-Step Solution

Answer

The solutions of (a) is there is no real number and (b) is $-9$

Part (a). Step 1. Given information

The root: $\sqrt{-169}$

Part (a) Step 2. Calculation

We have,

$$\begin{gathered} \sqrt{-169} \\ =\sqrt{-169} \mathrm{is} \mathrm{not} \mathrm{a} \mathrm{real} \mathrm{number} \end{gathered}$$

There is no real number whose square is $\sqrt{-169}$

Part (b) Step 1. Given information

The root: $-\sqrt{81}$

Part (b) Step 2. Calculation

We have,

$$\begin{gathered} -\sqrt{81} \\ =-9 \end{gathered}$$

Since, $9^2=81$and the negative is in front of the radical sign.

Therefore, the solution is $-9$