Q. 8.32 - An Introduction to General, Organic, and Biological Chemistry

Question

A gas sample has a temperature of $22 °C$with an unknown volume. The same gas has a volume of $456 mL$ when the temperature is  $86°C$, with no change in the pressure or amount of gas. What was the initial volume, in milliliters, of the gas?

Step-by-Step Solution

Answer

The initial volume, in milliliters, of the gas is $116.6 mL$$116.65mL$

Step 1: Given information

We need to find the initial volume in milliliters of the gas.

Step 2: Explanation

We will use charles law here as pressure and amount will not change 

let us assume initial volume to be $V_1$

we will get $\frac{V_1}{T_1}=\frac{V_2}{T_2}$

$$\begin{gathered} V_2=456 mL \\ {T}_1=22°C \\ {T}_2=86°C \end{gathered}$$

substituting the values, We get 

$$\begin{gathered} \frac{V_1}{22}=\frac{456}{86} \\ {V}_1=116.6 mL \end{gathered}$$