Q 8.16.

Question

In each Exercises 8.11-8.16, we provide a sample mean, sample size, and population standard deviation. In each case, perform the following tasks.

a. Find a 95% confidence interval for the population mean. (Note: You may want to review Example 8.2, which begins on the page 3l6)

b. Identify and interpret the margin of error.

c. Express the endpoints of the confidence interval in terms of the point estimate and the margin of error:

x^=55,n=16,σ=5

Step-by-Step Solution

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Answer

Part (a) The 95% confidence interval for the population mean is (52.5,57.5)

Part (b) The population means (μ) to within 2.5 with 95% confidence.

Part (c) The endpoint of the confidence interval is 55±2.5

1Part (a) Step 1: Given information

x^=55, n=16, σ=5

2Part (a) Step 2: Concept

The formula used: x¯±2σn

3Part (a) Step 3: Calculation

Compute a 95% confidence interval for the population mean.

Consider x¯=55, n=16, and σ=5

Empirical rule:

Property 1: Around 68% of the data set is located between (x¯-s, x¯+s)

Property 2: Approximately 95% of the data set is located between (x¯-2s, x¯+2s)

Property 3: Approximately 99.7% of the data set is located between (x¯-3s, x¯+3s)

Property 2 states that 95% of all observations are within two standard deviations of the mean on either side.

The 95% confidence interval for the population mean is,

x¯±2σn=55±2516=55±2.5=(55-2.5,55+2.5)=(52.5,57.5)

Thus, the 95% confidence interval for the population mean is (52.5,57.5)

4Part (b) Step 1: Explanation

From part (a), the margin of error is 2.5

It can be estimated that the population mean (μ) to within 2.5 with 95% confidence.

5Part (c) Step 1: Calculation

The confidence interval's endpoints should be expressed.

 endpoints = Point estimate ± Margin of error =55±2.5

Thus, the endpoints of the confidence interval are 55±2.5