Q. 8.140 - Intermediate Algebra

Question

For the function $g\left(x\right)=\sqrt[4]{5x+1},$find

$$\begin{gathered} \left(a\right) g\left(16\right) \\ \left(b\right) g\left(3\right). \end{gathered}$$

Step-by-Step Solution

Answer

The value of the function

(a)$$\begin{gathered} g\left(16\right)=3 \\ \left(b\right) g\left(3\right)=2 \end{gathered}$$

Step 1. Given information

$g\left(x\right)=\sqrt[4]{5x+1}$

We have to find $g\left(16\right) and g\left(3\right).$

Part (a) Step 1. Replace x = 16   in the given function respectively

$$\begin{gathered} g\left(16\right)=\sqrt[4]{5\left(16\right)+1}=\sqrt[4]{81} \\ g\left(16\right)=\sqrt[4]{3\times 3\times 3\times 3}=3 \end{gathered}$$

 

Part (b) Step 1. Replace x = 3 in the equation

$g\left(3\right)=\sqrt[4]{5\left(3\right)+1}=\sqrt[4]{16}=2$