Q 8.133.

Question

"Chips Ahoy! 1,000 Chips Challenge." As reported by B. Warner and J. Rutledge in the paper "Checking the Chips Ahoy! Guarantee" (Chanee, Vol. 12. Issue 1. pp. 10-14), a random sample of forty-two 18-ounce bags of Chips Ahoy! cookies yielded a mean of 1261.6 chips per bag with a standard deviation of 117.6 chips per bug.

a. Determine a 95% confidence interval for the mean number of chips per bag for all 18-ounce bags of Chips Ahoy! cookies, and interpret your result in words.

b. Can you conclude that the average 18-ounce bag of Chips Ahoy! cookies contain at least 1000 chocolate chips? Explain your answer.

Step-by-Step Solution

Verified
Answer

Part (a) (1,224.945,1,298.255)

Part (b) No.

1Part (a) Step 1: Given information

A representative sample of 4218-ounce bags of Chips The average cost of Ahoy! cookies were 1261.6 per bag, with a standard deviation of 117.6 per bug.

2Part (a) Step 2: Concept

The formula used: z=x¯±ta2sn

3Part (a) Step 3: Calculation

Calculate the 95% confidence interval for every Chips Ahoy! 18-ounce plastic bags of cookies, and write down your interpretation.

Consider x¯=1,261.6, n=42, s=117.6, and confidence level is 95%

From "Table IV Values of tα " the required value of tα2 for 95% confidence with 41  (=42-1) degrees of freedom is 2.020

Thus, the confidence interval is,

x¯±ta2sn=1,261.6±2.020117.642=1,261.6±2.020(18.146)=1,261.6±36.655=(1,224.945,1,298.255)

In order to understand your answer in words, For all 18-ounce packs of Chips, the 95 percent confidence interval for the mean amount of chips per bag Ahoy! Cookies are delicious. (1,224.945,1,298.255)

4Part (b) Step 1: Explanation

Because the value 1,000 does not appear in the interval obtained in section (a), it may be deduced that the average 18-ounce package of Chips Ahoy! cookies contain at least 1,000 chocolate chips (a).