Q. 8.113 - Intermediate Algebra

Question

Solve: $\sqrt{2r - 3 }+ 5 = 0.$

Step-by-Step Solution

Answer

The equation has no solution.

Step 1 Given equation is,

$\sqrt{2r - 3 }+ 5 = 0.$

The objective is, we need to find the solution for the given equation.

Step 2 To isolate the radical, subtract 5 on both sides.

$$\begin{gathered} \sqrt{2r - 3 }+ 5-5= 0-5 \\ \sqrt{2r - 3 }= -5 \end{gathered}$$

The equation has no solution. Because, the square root is equal to a negative number.