Q. 8

Question

Give the first five terms of the following recursively defined sequence: 

a1=2, and ak=ak-1+2  for k2.

Also, give a closed formula for the sequence.

Step-by-Step Solution

Verified
Answer

The first five terms of the sequence are: 2,4,6,8,10.

The closed formula for the sequence is ak=2k where k is any positive integer.

1Step 1. Given Information

A sequence is defined recursively as 

a1=2 and ak=ak-1+2 for k2.

2Step 2. Find the second and the third term

Substituting 2 for k in ak=ak-1+2 we get

a2=a2-1+2a2=a1+2a2=2+2a2=4

Again, substituting 3 for k in ak=ak-1+2 we get

a3=a3-1+2a3=a2+2a3=4+2a3=6

3Step 3. Find the fourth and the fifth term

In the equation ak=ak-1+2 substitute 4 for k.

a4=a4-1+2a4=a3+2a4=6+2a4=8

And lastly substitute 5 for k in the equation ak=ak-1+2 we get

a5=a5-1+2a5=a4+2a5=8+2a5=10

4Step 4. Find the closed formula

Hence the first five terms of the sequence are 2,4,6,8,10

Clearly, the given sequence is the sequence of consecutive even numbers.

Hence, the sequence can be defined by the closed formula ak=2k, where k is the positive integer.