Q. 7.82

Question

Ibuprofen, an anti-inflammatory drug in Advil, has the formula . C13H1802

Ibuprofen is an anti inflammatory.

  1. What is the molar mass of ibuprofen?
  2. How many grams of ibuprofen are in 0.525 mole?
  3. How many moles of C are in 12g of ibuprofen?
  4. How many moles of ibuprofen contain 1.22 x 1023 atoms of C?




Step-by-Step Solution

Verified
Answer

(a) The molar mass of ibuprofen is206.

(b) 108.15 g of ibuprofen are in 0.525 moles.

(c) 0.75 moles of C are in 12 g of ibuprofen.

(d) 0.015 moles of ibuprofen contains 1.22 x 1023 atoms of C.

1Part (a) Step 1: Given Information

We are given that Ibuprofen, an anti-inflammatory drug in Advil, has the formula C13H1802. and we need to fine the molar mass .

2Part (a) Step 2: Explanation

We are given that the chemical formula of ibuprofen C13H1802 and we have to find the molar mass Where C =12,O =16, H=1

m=12(amu)×13+16(amu)×2+18×1(amu)

m = 206 amu

Hence the molar mass of ibuprofen is 206 amu.

3Part (b) Step 1: Given Information

We need to find that How many grams of ibuprofen are in 0.525 mole .

4Part (b) Step 2: Explanation

We have to given that the moles of ibuprofen is 0.525 

We know that 

moles = weight in gmolar mass(amu)0.525 = W (g)206 (amu)W = 108.15 g

5Part (c) Step 1: Given Information

We need to find that How many moles of C are in 12.0 gof ibuprofen.

6Part (c) Step 2: Explanation

We see the formula C13H1802.1mol of ibuprofen = 13 mol ofC.

So the no of moles in 12 g of ibuprofen is 12/206.

Moles of ibuprofen are 0.058moles.

So 0.058 moles of ibuprofen are13×0.058 moles of C are 0.75 moles of C.

Hence the no of moles of carbon present in 12g of ibuprofen are0.75.

7Part (d) Step 1: Given Information

We need to find that How many moles of ibuprofen contain 1.22x1023 atoms of C?

8Part (d) Step 2: Explanation

We are given 1.22x1023 atoms of carbon.

So 

moles = 1.22×10236×1023moles = 0.20 mole

And we know that 

1mol of ibuprofen = 13 mol ofC.

0.20 moles of carbon contains =  0.213=0.015moles of ibuprofen.