Q. 7.6 - An Introduction to General, Organic, and Biological Chemistry

Question

Calculate each of the following quantities in $0.185$ moles of ${\mathrm{C}}_6{\mathrm{H}}_{14}\mathrm{O}$ :

1. moles of  $\mathrm{C}$
   
2. moles of  $\mathrm{O}$
   
3. atoms of  $\mathrm{H}$
4. atoms of  $\mathrm{C}$

Step-by-Step Solution

Answer

Quantities present in $0.185$ moles of ${\mathrm{C}}_6{\mathrm{H}}_{14}\mathrm{O}$ are:

1. $1.11$ moles of carbon
2.  $0.185$ moles of oxygen
3.  $4.4\times {10}^{22}$ atoms of hydrogen
4.  $6.68\times {10}^{23}$ atoms of carbon

Part (a) Step 1: Given Information

We need to find number of moles of $\mathrm{C}$ in $0.185$ moles of  ${\mathrm{C}}_6{\mathrm{H}}_{14}\mathrm{O}$

Part(a) Step 2: Explanation

One mole of ${\mathrm{C}}_6{\mathrm{H}}_{14}\mathrm{O}$ contains $6$ moles of  $\mathrm{C}$

So, moles of $\mathrm{C}$ in $0.185$ moles of ${\mathrm{C}}_6{\mathrm{H}}_{14}\mathrm{O}$ = $6\times 0.185=1.11$

Hence, $1.11$ moles of carbon present in $0.185$ moles of  ${\mathrm{C}}_6{\mathrm{H}}_{14}\mathrm{O}$

Part (b) Step 1: Given Information

We need to find number of moles of $\mathrm{O}$ in $0.185$ moles of  ${\mathrm{C}}_6{\mathrm{H}}_{14}\mathrm{O}$

Part(b) Step 2: Explanation

One mole of  ${\mathrm{C}}_6{\mathrm{H}}_{14}\mathrm{O}$ contains one mole of oxygen

So, moles of oxygen in $0.185$ moles of  ${\mathrm{C}}_6{\mathrm{H}}_{14}\mathrm{O}$ =  $0.185\times 1=0.185$

Hence,$0.185$ moles of oxygen is  present in $0.185$ moles of ${\mathrm{C}}_6{\mathrm{H}}_{14}\mathrm{O}$ .

Part (c) Step 1: Given Information

We need to find number of  atoms of $\mathrm{H}$ in $0.185$ moles of  ${\mathrm{C}}_6{\mathrm{H}}_{14}\mathrm{O}$

Part(c) Step 2: Explanation

One mole of  ${\mathrm{C}}_6{\mathrm{H}}_{14}\mathrm{O}$ contains $14$ mole of $\mathrm{H}$ in it.

Number of atoms of $\mathrm{H}$ in $0.185$ moles of ${\mathrm{C}}_6{\mathrm{H}}_{14}\mathrm{O}$ =  $0.185\times 4\times 6.02\times {10}^{23}=4.4\times {10}^{22}$

Hence, $4.4\times {10}^{22}$  atoms are present.

Part (d) Step 1: Given Information

We need to find number of  atoms of $\mathrm{C}$ in $0.185$ moles of  ${\mathrm{C}}_6{\mathrm{H}}_{14}\mathrm{O}$

Part(d) Step 2: Explanation

One mole of  ${\mathrm{C}}_6{\mathrm{H}}_{14}\mathrm{O}$ contains $6$ mole of $\mathrm{C}$ in it.

Number of atoms of $\mathrm{C}$ in $0.185$ moles of data-custom-editor="chemistry" ${\mathrm{C}}_6{\mathrm{H}}_{14}\mathrm{O}$ =  $$\begin{gathered} 0.185\times 6\times 6.02\times {10}^{23} \\ =6.68\times {10}^{23} \end{gathered}$$

Hence,  $6.68\times {10}^{23}$ atoms are present.