Q 74E - Intermediate Algebra

Question

In the following exercises, factor each trinomial of the form 

$$\begin{gathered} x^2 + bx + C. \\ 6n-7+ n² \end{gathered}$$

Step-by-Step Solution

Answer

The binomial factors of the equations are $(n+7)(n-1)$.

Step 1. Given information and rewriting the equation in general from.

The given equation is 

$6n-7+ n²$

The general form is 

$n²+6n-7$

Step 2. Writing factors as two binomial with n.

The factors should be written as two binomials with n as the first term.

$(n )(n )$

The product of the two numbers is 7, and their sum is 6. Because the third term sign is negative, the sum seems to be a difference.

$\left[\begin{array}{cc}\mathrm{Factors}& 7\\ & 1\\ \mathrm{Difference}& 6\end{array}\right]$

So form of binomial is $(n 7)(n 1)$.

Step 3. Finding factors

The larger binomial second term is also positive because the second trinomial term is positive.

Because the third trinomial term is negative, the binomial signs are transposed.

The binomial factors are as follows:

$(n+7)(n-1)$

Step 4. Checking the factors

$$\begin{gathered} \mathrm{Check}: \mathrm{Multiply} \mathrm{the} \mathrm{factors}. \\ (n+7)(n-1)=n²-n+7n-7 \left[\mathrm{Multiply}\right] \\ = n²+6n-7 \mathrm{True} [\mathrm{Group} \mathrm{the} \mathrm{like} \mathrm{terms}] \end{gathered}$$