Q. 7.13 - An Introduction to General, Organic, and Biological Chemistry

Question

Calculate the molar mass for each of the following : 

a. ${\mathrm{AlF}}_3$      b. ${\mathrm{C}}_2{\mathrm{H}}_4{\mathrm{Cl}}_2$     c. ${\mathrm{SnF}}_2$

Step-by-Step Solution

Answer

a. The molar mass of ${\mathrm{AlF}}_3$ is $83.95 \mathrm{g}$

b. The molar mass of ${\mathrm{C}}_2{\mathrm{H}}_4{\mathrm{Cl}}_2$ is $98.92 \mathrm{g}$

c. The molar mass of ${\mathrm{SnF}}_2$ is $156.67 \mathrm{g}$

Part (a) Step 1 : Given information

We have to calculate the molar mass of  ${\mathrm{AlF}}_3$

Part (a) Step 2 : Simplification

We know that,

Molar mass of one Al atom = $26.98 \mathrm{g}$

Molar mass of one $\mathrm{F}$  atom = $18.99 \mathrm{g}$

So, molar mass of ${\mathrm{AlF}}_3$=$26.98 + 3\left(18.99\right)$ = $83.95 \mathrm{g}$

Part (b) Step 1 : Given information

We have to calculate the molar mass of  ${\mathrm{C}}_2{\mathrm{H}}_4{\mathrm{Cl}}_2$

Part (b) Step 2 : Simplification

We know that,

Molar mass of one $\mathrm{C}$ atom = $12.01 \mathrm{g}$

Molar mass of one $\mathrm{H}$  atom = $1.00 \mathrm{g}$

Molar mass of one $\mathrm{Cl}$ atom = $35.45 \mathrm{g}$

So, molar mass of ${\mathrm{C}}_2{\mathrm{H}}_4{\mathrm{Cl}}_2$ = $2\left(12.01\right) + 4\left(1.00\right) + 2\left(35.45\right)$ = $98.92 \mathrm{g}$

Part (c) Step 1 : Given information

We have to calculate the molar mass of  ${\mathrm{SnF}}_2$

Part (c) Step 2 : Simplification

We know that,

Molar mass of one $\mathrm{Sn}$ atom =$118.69 \mathrm{g}$

Molar mass of one $\mathrm{F}$ atom = $18.99 \mathrm{g}$

So, molar mass of ${\mathrm{SnF}}_2$ = $118.69 + 2\left(18.99\right)$ = $156.67 \mathrm{g}$