Q. 7.10 - An Introduction to General, Organic, and Biological Chemistry

Question

Benadryl is an over-the-counter drug used to treat allergy symptoms. The formula of Benadryl is ${\mathrm{C}}_{17}{\mathrm{H}}_{21}\mathrm{NO}$.
a. How many moles of $\mathrm{C}$ are present in $0.733$ mole of Benadryl?
b. How many moles of $\mathrm{H}$ are present in $2.20$ moles of Benadryl?
c. How many moles of $\mathrm{N}$ are present in $1.54$ moles of Benadryl? 

Step-by-Step Solution

Answer

Our required answers are:

1. $12.461$ moles of data-custom-editor="chemistry" $\mathrm{C}$ present in $0.733$ moles Benadryl .
2. $46.20$ moles of data-custom-editor="chemistry" $\mathrm{H}$ present in $2.20$ moles Benadryl.
3.  $1.54$ moles of data-custom-editor="chemistry" $\mathrm{N}$ are present in $1.54$ moles of Benadryl.

Part(a) Step 1: Given Information

We need to find moles of $\mathrm{C}$ in $0.733$ moles of Benadryl .

Part(a) Step 2: Explanation

Using equalities and conversion factor using subscripts:

One mole of  ${\mathrm{C}}_{17}{\mathrm{H}}_{21}\mathrm{NO}$ =  $17$ moles of $\mathrm{C}$

Conversion Factor= $\frac{17 mole \mathrm{C}}{1 \mathrm{mole} {\mathrm{C}}_{17}{\mathrm{H}}_{21}\mathrm{NO}}$

Moles of  in  moles of  naproxen = $$\begin{gathered} \frac{17 mole \mathrm{C}}{1 \mathrm{mole} {\mathrm{C}}_{17}{\mathrm{H}}_{21}\mathrm{NO}}\times 0.733 \mathrm{mole} {\mathrm{C}}_{17}{\mathrm{H}}_{21}\mathrm{NO} \\ =12.461 \mathrm{mole} \mathrm{C} \end{gathered}$$

Hence, $12.461$ moles of  present in $0.733$ moles  Benadryl  .

Part(b) Step 1: Given Information

We need to find moles of $\mathrm{H}$ in $2.20$ moles of Benadryl .

Part(b) Step 2: Explanation

Using equalities and conversion factor using subscripts:

One mole of  ${\mathrm{C}}_{17}{\mathrm{H}}_{21}\mathrm{NO}$=  $21$ moles of $\mathrm{H}$

Conversion Factor= $\frac{21 mole \mathrm{H}}{1 mole {\mathrm{C}}_{17}{\mathrm{H}}_{21}\mathrm{NO}}$

Moles of  in  moles of  naproxen = $$\begin{gathered} \frac{21 mole \mathrm{H}}{1 mole {\mathrm{C}}_{17}{\mathrm{H}}_{21}\mathrm{NO}}\times 2.20 mole {\mathrm{C}}_{17}{\mathrm{H}}_{21}\mathrm{NO} \\ =46.20 mole \mathrm{H} \end{gathered}$$

Hence, $46.20$ moles of $\mathrm{H}$ present in $2.20$ moles  Benadryl  .

Part(c) Step 1: Given Information

We need to find moles of $\mathrm{N}$ in $1.54$ moles of Benadryl .

Part(c) Step 2: Explanation

Using equalities and conversion factor using subscripts:

One mole of  ${\mathrm{C}}_{17}{\mathrm{H}}_{21}\mathrm{NO}$=  $1$ moles of $\mathrm{N}$

Conversion Factor= $\frac{1 mole \mathrm{N}}{1 mole {\mathrm{C}}_{17}{\mathrm{H}}_{21}\mathrm{NO}}$

Moles of  in  moles of  naproxen = $$\begin{gathered} \frac{1 mole \mathrm{N}}{1 mole {\mathrm{C}}_{17}{\mathrm{H}}_{21}\mathrm{NO}}\times 1.54 mole {\mathrm{C}}_{17}{\mathrm{H}}_{21}\mathrm{NO} \\ =1.54 mole \mathrm{N} \end{gathered}$$

Hence,  $1.54$ moles of $\mathrm{N}$ present in $1.54$ moles  Benadryl  .