Q. 6.92 - Intermediate Algebra

Question

Solve, $36x^2=121$

Step-by-Step Solution

Answer

The value is $x=\pm \frac{11}{6}$

Step 1: Given information

Given the equation ,$36x^2=121$ 

Step 2: Write in standard form

Writing in standard form, we get

$$\begin{gathered} 36x^2=121 \\ 36x^2-121=0 \\ (6x-11)(6x+11)=0 \\ x=\frac{11}{6}, -\frac{11}{6} \end{gathered}$$

Step 3: Checking the values

Checking, we get

$$\begin{gathered} 36{\left(\frac{11}{6}\right)}^2=121 \\ 36\times \frac{121}{36}=121 \\ 121=121 \end{gathered}$$

This is true

Step 4: Checking another value

Checking the value, we get

$$\begin{gathered} 36{(-\frac{11}{6})}^2=12136\times \frac{121}{36}=121 \\ 121=121 \end{gathered}$$

So this is true