Q. 6.92

Question

A variable is normally distributed with a mean of 0 and standard deviation 4. Find the percentage of all possible values of the variable.

a. lie between -8 and 8 .

b. exceed -1.5,

c. are less than 2.75.

Step-by-Step Solution

Verified
Answer

a) 95.44%

b) 64.80%

c) 74.59%

1Step 1: Given Information (Part a)

To find the percentage of observations that lie between -8 and  8.

2Step 2: Explanation (Part a)

Calculate the z-scores as follows:

 z=-8-04=-2

z=8-04=2

As a result, the observations between -8 and -8have the same z-scores as the z- scores between -2 and 2.

The proportions that are less than the z- scores are taken from Table II in Appendix A.

-2and -2 are equal to 0.0228and 0.9772, respectively.

The difference between the values in Table II is then used to calculate the percentage of all observations:

0.9772-0.0228 = 0.9544

95.44 percent of the time

3Step 1: Given Information (Part b)

To find the percentage of observations that are greater than -1.5.

4Step 2: Explanation(Part b)

Calculate the z - score:

z=-1.5-04-0.38

As a result, observations greater than 5 correspond to z- scores greater than -0.38.

The proportion of z- scores greater than -0.38 is shown in Table II of Appendix A.

1-0.3520 = 0.6480

=64.80 

5Step 1: Given Information (Part c)

To find The percentage of observations that are less than 2.75.

6Step 2: Explanation (Part c)

Determine the z - score:


z=2.75-040.69


Therefore the observations less than 2.75are the same as the z- scores less than 0.69. From Table II in Appendix A, the proportion of z - scores less than 0.69 is

0.7459=74.59 %.