Q. 6.8
Question
Complete the following table.
Step-by-Step Solution
VerifiedThe completed table is given below,
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The area is not found in the table. So, we can use area closest to which are and . Here, we use the average of the two -scores and , which is . Thus, the -score having area to its left under the standard normal curve is . By applying the symmetry property the -score having area to its right under the standard normal curve is, .
The value of -score for the area in the table is, . Thus, the -score having area to its left under the standard normal curve is, . By applying the symmetry property the -score having area to its right under the standard normal curve is .
The -score for the area is not found in the table. So, we use the area closest to , which is . The -score corresponding to that area is, . Thus, the -score having area to its left under the standard normal curve is, . By applying the symmetry property the -score having area to its right under the standard normal curve is, .
The area has no value in the table. So, we use area closest to , which are and . Here, we use the average of the two -scores and , which is . Thus, the -score having area to its left under the standard normal curve is, . By applying the symmetry property the -score having area to its right under the standard normal curve is, .