Q. 6.76 - Intermediate Algebra

Question

Factor completely: $27x{y}^3+48xy$

Step-by-Step Solution

Answer

The required factors are $3xy(9y^2+16)$

Step 1. Given Information

The given expression is $27x{y}^3+48xy$

Step 2. Calculation

We will factor the expression by taking the common factor outside the paranthesis. 

$27x{y}^3+48xy=3xy(9y^2+16)$

Step 3. Check

We will verify the obtained factors by multiplying them.

$3xy(9y^2+16)=27x{y}^3+48xy$