Q-6.7.

Question

  1. If X has a gamma distribution with parameters (n,𝜆) what is the distribution of cX, c>0
  2. Show that 𝒳2n22𝜆 has a gamma distribution with parameters (n,𝝀) when n is a positive integer and 𝒳2n2 is a chi-squared random variable with 2n degrees of freedom

Step-by-Step Solution

Verified
Answer
  1. cX~𝚪(t,𝛌/c)
  2. 𝒳2n22n~𝚪(n,𝜆)
1Step 1. Content Introduction.

The derivative of the CDF is the probability density function f(x), abbreviated PDF if it exists. A distribution function Fx  describes each random variable X.

2Step 2. Explanation (Part a).

We are given that X has a Gamma distribution with parameters t and λ. Let's find the CDF of cX. We have that

FcX(z)=P (cXz)=P(Xzc)=FX(zc)

Hence,

fcX(z)=ddzFX(zc)=fX(zc).1c

which implies that,

fcX(z)=λtτ(t)(zc)t-1e-λzc.1c=(λc)tτ(t)zt-1e-λcz

So, we see that cX~𝚪 (t,λc)

3Step 3. Explanation (Part b)

Take any z > 0 and define Z: 12λX22n, we have that

Fz(z)=P(Zz)=P(12λX22nz)=P(X22n2λz)=Fx22n(2λz)

Hence we get that

fZ(z)=ddzFz(z)=ddzFx22n(2λz)=λnτ(n)zn-1e-λz

A chi-squared random variable with 2n degrees of freedom can be regarded as being the sum of n independent chi-square random variables each with 2 degrees of freedom (which for Example is equivalent to an exponential random variable with a parameter ). Hence Proposition X22n is a gamma random variable with parameters (n,1/2) and the results now follow from part (a)