Q. 6.69 - Intermediate Algebra

Question

Factor completely: $8y^3+16y^2-24y$

Step-by-Step Solution

Answer

The required answer is $8y(y+3)(y-1)$

Step 1. Given Information

The given expression is $8y^3+16y^2-24y$

Step 2. Calculation

We will use the middle term splitting method to find the factors of the given expression.

$$\begin{gathered} 8y^3+16y^2-24y=8y(y^2+2y-3) \\ =8y(y^2+3y-y-3) \\ =8y\left(y\right(y+3)-1(y+3\left)\right) \\ =8y(y+3)(y-1) \end{gathered}$$