Q. 6.66

Question

Use Table to obtain the areas under the standard normal curve. Sketch a standard normal curve and shade the area of interest in each problem.

Find the area under the standard normal curve that lies

a. either to the left of -1 or to the right of 2.

b. either to the left of -2.51 or to the right of -1.

Step-by-Step Solution

Verified
Answer

(a) The area under the standard normal that lies either to the left of -1 or to the right of 2 will be 0.1815

(b) The area under the standard normal that lies either to the left of -2.51 or to the right of -1 is

0.8473

1Part(a) Step 1: Given Information

2Part(a) Step 2: Explanation

To the left of -1 is the following area:

Because the given integer -1 is negative, the conventional normal table of negative z scores is applied. To begin, move down the right hand column labeled' z 'to -1.0 and then across the row to the column labeled'0.00 'to get 0.1587.

Right-hand side of 2:

Right-hand area =1 - Left-hand area

Because the given number 2 is positive, the typical normal table of positive z scores is applied. To begin, move down the left hand column labeled' z 'to 2.0 and then across the row to the column labeled' 0.00 'to get 0.9772

Consequently the area under the standard normal that lies to the right of 2.0 is 1-0.9772=0.0228

The area is 0.1587+0.0228=0.1815.

3Part(b) Step 1: Given Information

4Part(b) Step 2: Explanation

Because the given integer -2.51 is negative, the typical normal table of negative z scores is utilised in the area to the left of -2.51. To begin, move down the right hand column labelled z 'to -2.5 and then across the row to the column labeled' 0.01 'to get 0.0060.

Area to the right of -1 :

Area to the right =1 - Area to the left

Because the given integer -1 is negative, the conventional normal table of negative z scores is applied. To begin, move down the right hand column labeled' z 'to -1.0 and then across the row to the column labeled' 0.00 'to get 0.1587.

Thus, the area under the standard normal that lies to the right of -1 is 1-0.1587=0.8413

The area is 0.0060+0.8413=0.8473.