Q. 6.64

Question

Determine the area under the standard normal curve that lies between 

a. -0.88 and 2.24.

b. -2.5 and -2.

c. 1.48 and 2.72.

d. -5.1 and 1.

Step-by-Step Solution

Verified
Answer

Part a: The area under the standard normal curve that lies between -0.88 and 2.24 is, 0.7981.

Part b: The area under the standard normal curve that lies between -2.5 and -2 is, 0.0166.

Part c: The area under the standard normal curve that lies between 1.48 and 2.72 is, 0.0661.

Part d: The area under the standard normal curve that lies between -5.1 and 1 is, 0.8413.

1Part a Step 1 . Given information

We need to find the area for the given values between them.

2Part a Step 2 . Let us analyze the give values and find the area for it.

The area under the standard normal curve that lies between -0.88 and 2.24 equals the area to the left of 2.24 minus the area to the left of -0.88.Standard normal table shows that these latter two areas are 0.9875 and 0.1894,respectively. So, the required area is, 0.9875-0.1894=0.7981.

3Part a Step 3 . Let us draw a curve which shows the obtained area in it.



4Part b Step 1 . Let us analyze the given values and find the area for it.

The area under the standard normal curve that lies between -2.5 and -2 equals the area to the left of -2 minus the area to the left of -2.5. Standard normal table shows that these latter two areas are 0.0228 and 0.0062. So, the required area is, 0.0228-0.0062=0.0166.

5Part b Step 2 . Le us draw a curve which shows the obtained area on it.



6Part c Step 1 . Let us analyze the give values and find the area between them.

The area under the standard normal curve that lies between 1.48 and 2.72 equals the area to the left of 2.72 minus the area to the left of 1.48.Standard normal table shows that these latter two areas are 0.9967 and 0.9306, respectively. So, the required area is. 0.9967-0.9306=0.0661.

7Part c Step 2 . Let us draw a curve which shows the obtained area in it.



8Part d Step 1 . Let us analyze the given values and find the area between them.

The area under the standard normal curve that lies between -5.1 and 1 equals the area to the left of 1 minus the area to the left of -5.1. Standard normal table shows that these latter two areas are 0.8413 and 0.0000,respectively. So, the required area is, 0.8413-0.0000=0.8413.

9Part d Step 2 . Let us draw a curve which shows the obtained area in it.