Q. 6.59
Question
Use Table II to obtain the areas under the standard normal curve required in Exercises 6.59-6.66. Sketch a standard normal curve and shade the area of interest in each problem.
Determine the area under the standard normal curve that lies to the left of
a.
b.
c.
d.
Step-by-Step Solution
Verifieda. The area under the standard normal curve that lies to the left of is
b. The area under the standard normal curve that lies to the left of is .
c. The area under the standard normal curve that lies to the left of is .
d. The area under the standard normal curve that lies to the left of is .
Use Table II to obtain the areas under the standard normal curve.
Determine the area under the standard normal curve that lies to the left of
Because the given number is positive, the conventional normal table of positive scores is applied. The number obtained by moving down the left hand column labelled to and then across the row to the column labeled is .
As a result, the area beneath the standard normal to the left of is .
Use Table II to obtain the areas under the standard normal curve.
Determine the area under the standard normal curve that lies to the left of .
Because the given number is negative, the conventional normal table of negative scores is applied. The number obtained by travelling down the right-hand column labelled to and then across the row to the column labelled is .
As a result, the area to the left of under the standard normal is
Use Table II to obtain the areas under the standard normal curve.
Determine the area under the standard normal curve that lies to the left of
The typical table is employed. To begin, reduce the number in the left-hand column labeled to and then move across the row to the column labeled The result is .
As a result, the region to the left of under the usual normal is .
Use Table II to obtain the areas under the standard normal curve.
Determine the area under the standard normal curve that lies to the left of
Because the given number is negative, the conventional normal table of negative scores is applied. First, move down to in the right-hand column labelled then across the row to the column labelled and we will get
As a result, the region beneath the usual normal to the left of is