Q. 6.53 - An Introduction to General, Organic, and Biological Chemistry

Question

Write the formula for each of the following molecular compounds:

a. oxygen difluoride

b. boron trichloride

c. dinitrogen trioxide

d. sulfur hexafluoride

Step-by-Step Solution

Answer

(a) The formula of the compound is $O{F}_2$

(b) The formula of the compound is $BC{l}_3$

(c) The formula of the compound is $N_2{O}_3$

(d) The formula of the compound is $S{F}_6$

Part (a) Step 1: Given information

We need to find out the chemical formula of the given compound i.e. oxygen difluoride

Part (a) Step 2: Explanation

We know that,

The symbol of oxygen is, $O$

And the symbol of fluoride is, $F$

And the prefix of fluoride is di which means there are two fluorine atom

So, the subscript of oxygen is one that has no means to write and the subscript of fluorine is two

Therefore, according to the name of the given compounds, 

The formula is, $O{F}_2$

Part (b) Step 1: Given information

We need to find out the chemical formula of the given compound i.e. boron trichloride

Part (b) Step 2: Explanation

We know that,

The symbol of boron is, $B$

And the symbol of chloride is, $Cl$

And the prefix of chloride is tri which means there are three chlorine atom

So, the subscript of boron is one that has no means to write and the subscript of chlorine is three

Therefore, according to the name of the given compounds, 

The formula is, $BC{l}_3$

Part (c) Step 1: Given information

We need to find out the chemical formula of the given compound i.e. dinitrogen trioxide

Part (c) Step 2: Explanation

We know that,

The symbol of nitrogen is, $N$

And the symbol of oxide is, $O$

And the prefix of nitrogen is di which means there are two nitrogen atoms and that of oxide is tri which means three oxygen atoms

So, the subscript of nitrogen is two and the subscript of oxygen is three

Therefore, according to the name of the given compounds, 

The formula is, $N_2{O}_3$

Part (d) Step 1: Given information

We need to find out the chemical formula of the given compound i.e. sulfur hexafluoride

Part (d) Step 2: Explanation

We know that,

The symbol of sulfur is, $S$

And the symbol of fluoride is, $F$

And the prefix of fluoride is hexa which means there are six fluorine atom

So, the subscript of sulfur is one that has no means to write and the subscript of fluorine is six

Therefore, according to the name of the given compounds, 

The formula is, $S{F}_6$