Q. 6.50 - An Introduction to General, Organic, and Biological Chemistry

Question

Name each of the following molecular compounds: 

a. $Si{F}_4$ 

b.$IB{r}_3$ 

c. $C{O}_2$ 

d.$N_2{F}_2$

e. $N_2{S}_3$

Step-by-Step Solution

Answer

(a) The molecular compound is silicon tetrafluoride

(b) The molecular compound is iodine tribromide

(c) The molecular compound is carbon dioxide

(d) The molecular compound is dinitrogen difluoride

(e) The molecular compound is dinitrogen trisulfide

Part (a) Step 1: Given information

We need to find the molecular name of $Si{F}_4$

Part (a) Step 2: Explanation

We know that,

The first nonmetal is $Si$ i.e. silicon

And second nonmetal $F$ i.e. fluoride

As the no. of atoms or subscript of fluoride atom is $4$

Therefore, the compound is, silicon tetrafluoride

Part (b) Step 1: Given information

We need to find the molecular name of $IB{r}_3$

Part (b) Step 2: Explanation

We know that,

The first nonmetal is $I$ i.e. iodine

And second nonmetal $Br$ i.e. bromide

As the no. of atoms or subscript of bromide atom is $3$

Therefore, the compound is, iodine tribromide 

Part (c) Step 1: Given information

We need to find the molecular name of $C{O}_2$

Part (c) Step 2: Explanation

We know that,

The first nonmetal is $C$ i.e. carbon

And second nonmetal $O$ i.e. oxide

As the no. of atoms or subscript of oxide atom is $2$

Therefore, the compound is, carbon dioxide

Part (d) Step 1: Given information

We need to find the molecular name of $N_2{F}_2$

Part (d) Step 2: Explanation

We know that,

The first nonmetal is $N$ i.e. nitrogen

And second nonmetal $F$ i.e. fluoride

As the no. of atoms or subscript of nitrogen and fluoride atom is $2$ and $2$

Therefore, the compound is, dinitrogen difluoride

Part (e) Step 1: Given information

We need to find the molecular name of $N_2{S}_3$

Part (e) Step 2: Explanation

We know that,

The first nonmetal is $N$ i.e. nitrogen

And second nonmetal $S$ i.e. sulfide

As the no. of atoms or subscript of nitrogen and sulfide atom is $2$ and $3$

Therefore, the compound is, dinitrogen trisulfide