Q. 6.45 - An Introduction to General, Organic, and Biological Chemistry

Question

Name each of the following ionic compounds:

a. $Zn{\left(C_2{H}_3{O}_2\right)}_2$, cold remedy 

b. $M{g}_3{\left(P{O}_4\right)}_2$, antacid

c. $N{H}_{4}Cl$, expectorant

d. ${\mathrm{NaHCO}}_3$, corrects pH imbalance

e. $NaN{O}_2$, meat preservative

Step-by-Step Solution

Answer

(a) The ionic compound is zinc acetate

(b) The ionic compound is magnesium phosphate

(c) The ionic compound is ammonium chloride

(d) The ionic compound is sodium bicarbonate

(e) The ionic compound is Sodium nitrate

Part (a) Step 1: Given information

We need to find the name of the given ionic compound i.e. $Zn{\left(C_2{H}_3{O}_2\right)}_2$

Part (a) Step 2: Explanation

The substance is:

$Zn{\left(C_2{H}_3{O}_2\right)}_2$

The molecule's polyatomic ion is $C_2{H}_3{O}_2$, and there are two of these ions in the compound. The charge of the polyatomic ion should be $-1$ because the other atom is $Zn$, which has a charge of $+2$. As a result, the polyatomic ion $C_2{H}_3{O}_2^{-}$, which is acetate.

The cation of this molecule is zinc, and the anion is acetate. As a result, the compound's name is zinc acetate.

Part (b) Step 1: Given information

We need to find the name of the given ionic compound i.e. $M{g}_3{\left(P{O}_4\right)}_2$

Part (b) Step 2: Explanation

The substance is:

$M{g}_3{\left(P{O}_4\right)}_2$

$P{O}_4$ is the polyatomic ion in the compound, which consists of two ions. Because the other atom is $Mg$, which has a charge of $+2$, and there are three atoms, the polyatomic ion should have a charge of $-3$. As a result, the polyatomic ion is $P{O}_4^{3-}$, or the phosphate ion.

The anion in the molecule is the phosphate ion, whereas the cation is magnesium. As a result, the compound's name is magnesium phosphate

Part (c) Step 1: Given information

We need to find the name of the given ionic compound i.e. $N{H}_{4}Cl$

Part (c) Step 2: Explanation

The substance is:

$N{H}_{4}Cl$

The compound's polyatomic ion is $N{H}_4$. The charge of the polyatomic ion should be $+1$ because the other atom is Cl, which has a charge of $-1$. As a result, the polyatomic ion is $N{H}_4^{+}$, which stands for ammonium.

The cation of the chemical is ammonium, and the anion is chloride. As a result, the compound's name is ammonium chloride.

Part (d) Step 1: Given information

We need to find the name of the given ionic compound i.e. $NaHC{O}_3$

Part (d) Step 2: Explanation

The substance is:

$NaHC{O}_3$

$HC{O}_3$ is the polyatomic ion in the molecule. The charge of the polyatomic ion should be $-1$ because the other atom is $Na$, which has a charge of $+1$. As a result the polyatomic ion is $HC{O}_3^{-}$ the ion bicarbonate

The sodium cation is present in the molecule, while the bicarbonate anion is present. As a result, the compound's name is sodium bicarbonate

Part (e) Step 1: Given information

We need to find the name of the given ionic compound i.e. $NaN{O}_2$

Part (e) Step 2: Explanation

The substance is:

$NaN{O}_2$

The compound's polyatomic ion is $N{O}_2$. The charge of the polyatomic ion should be $-1$ because the other atom is $Na$, which has a charge of $+1$. As a result, the polyatomic ion is $N{O}_2^{-}$, the nitrite ion.

The sodium cation is present in the molecule, while the nitrite anion is present. As a result, the compound's name is sodium nitrite