Q. 6.44 - An Introduction to General, Organic, and Biological Chemistry

Question

Write the formula for the polyatomic ion and name each of the following compounds:

a. ${\mathrm{MnCO}}_3$             b. ${\mathrm{Au}}_2{\mathrm{SO}}_4$

c. ${\mathrm{Mg}}_3{\left({\mathrm{PO}}_4\right)}_2$       d. $\mathrm{Fe}{\left({\mathrm{HCO}}_3\right)}_3$

Step-by-Step Solution

Answer

a. The name of the compound ${\mathrm{MnCO}}_3$ is manganese carbonate and ${\mathrm{CO}}_3^{2-}$ is polyatomic ion.

b. The name of the compound ${\mathrm{Au}}_2{\mathrm{SO}}_4$ is gold sulfate and ${\mathrm{SO}}_4^{2-}$ is polyatomic ion.

c. The name of the compound ${\mathrm{Mg}}_3{\left({\mathrm{PO}}_4\right)}_2$ is Magnesium phosphate and ${\mathrm{PO}}_4^{3-}$ is polyatomic ion.

d. The name of the compound $\mathrm{Fe}{\left({\mathrm{HCO}}_3\right)}_3$ is iron hydrogen carbonate and ${\mathrm{HCO}}_3^{-}$ is polyatomic ion.

Part (a) Step 1 : Given information

We have to write the formula for the polyatomic ion and name of ${\mathrm{MgCO}}_3$ compound.

Part (a) Step 2 : Simplification

We know that ${\mathrm{MnCO}}_3$ can be written as ${\mathrm{Mn}}^{2+}$ and ${\mathrm{CO}}_3^{2-}$ in ionic form,

So, its polyatomic ion is ${\mathrm{CO}}_3^{2-}$  and its name is manganese carbonate.

Part (b) Step 1 : Given information

We have to write the formula for the polyatomic ion and name of ${\mathrm{Au}}_2{\mathrm{SO}}_4$ compound.

Part (b) Step 2 : Simplification

We know that ${\mathrm{Au}}_2{\mathrm{SO}}_4$ can be written as ${\mathrm{Au}}^{+}$ and ${\mathrm{SO}}_4^{2-}$ in ionic form,

So, its polyatomic ion is ${\mathrm{SO}}_4^{2-}$  and its name is gold sulphate.

Part (c) Step 1 : Given information

We have to write the formula for the polyatomic ion and name of ${\mathrm{Mg}}_3{\left({\mathrm{PO}}_4\right)}_2$ compound.

Part (c) Step 2 : Simplification

We know that ${\mathrm{Mg}}_3{\left({\mathrm{PO}}_4\right)}_2$ can be written as ${\mathrm{Mg}}^{2+}$ and ${\mathrm{PO}}_4^{3-}$ in ionic form,

So, its polyatomic ion is ${\mathrm{PO}}_4^{3-}$  and its name is magnesium phosphate.

Part (d) Step 1 : Given information

We have to write the formula for the polyatomic ion and name of $\mathrm{Fe}{\left({\mathrm{HCO}}_3\right)}_3$ compound.

Part (d) Step 2 : Simplification

We know that $\mathrm{Fe}{\left({\mathrm{HCO}}_3\right)}_2$ can be written as ${\mathrm{Fe}}^{2+}$ and ${\mathrm{HCO}}_3^{-}$ in ionic form,

So, its polyatomic ion is ${\mathrm{HCO}}_3^{-}$  and its name is iron hydrogen carbonate.