Q. 63 - Calculus

Question

Calculate each limit in Exercises 35–80. 

$\underset{x\to 3^{+}}{lim}\ln (x^2-9)$

Step-by-Step Solution

Answer

The limit is $-\infty$

Step 1. Given information

The given expression is  $\underset{x\to 3^{+}}{lim}\ln (x^2-9)$

Step 2. Calculation

The limit is calculated as below, 

$$\begin{gathered} \underset{x\to 3^{+}}{lim}\ln (x^2-9)=\ln (3^2-9) \\ =\ln (9-9) \\ =\ln \left(0\right) \\ =-\infty \end{gathered}$$