Q 6.21TI - Intermediate Algebra

Question

Factor $9m+m^2+18$

Step-by-Step Solution

Answer

The factored form is $(m+3)(m+6)$

Step 1: Given information

Given polynomial $9m+m^2+18$

Step 2: Arranging in decreasing order

The polynomial in decreasing order is $m^2+9m+18$

Step 3: Writing as parentheses

The polynomial can be written as $(m )(m )$. The table is 

Factors of $18$	Sum of factors
$1,18$	$1+18=19$
$2,9$	$2+9=11$
$3,6$	$3+6=9$

Step 4: Use m , n as last terms of factors and form the factored polynomial

Here 

$$\begin{gathered} m,n=3,6 \\ m+n=9 \\ m\times n=18 \end{gathered}$$

Step 5: Substitute the values and form the factored form

The factored form is $(x+3)(x+6)$