Q. 62

Question

62. Blink When two lights close together blink alternately, we “see” one light moving back and forth if the time between blinks is short. What is the
longest interval of time between blinks that preserves the illusion of motion? Ask subjects to turn a knob that slows the blinking until they “see” two lights rather than one light moving. A report gives the results in the form “mean plus or minus the standard error of the mean.” Data for 12 subjects are summarized as 251±45 (in milliseconds).
(a) Find the sample standard deviation sx for these measurements. Show your work.
(b) Explain why the interval 251±45 is not a confidence interval.

Step-by-Step Solution

Verified
Answer

(a) The standard deviation sx for the measurements is 155.8846

(b) The provided interval 251±45 is not a confidence interval, because t*is unknown.

1Part (a) Step 1 : Given information

Data for 12 subjects are summarized as 251±45 (in milliseconds). To Find the sample standard deviation sx for these measurements.  

2Part (a) Step 2 : Explanation

The standard deviation is divided by the square root of the sample size to get the standard error of the mean.

Standard error of mean is  E¯=sxn, and multiply with n on both sides.

Then, s=E¯×n.

where, Sample size n is 12, Standard error of mean E¯=45, and the population mean x¯ is 251.
s=E¯×n  =45×12  =155.8846
Therefore, the standard deviation is 155.8846.

3Part (b) Step 1 : Given Information

To explain why the provided interval  251±45 is not a confidence interval.

4Part (b) step 2 : Explanation

The confidence interval is calculated by using the formula=x¯±t*×E¯.

The interval in the problem  is x¯±E¯.

And,  t* is unknown.

As a result, the provided interval is not a confidence interval.