Q. 6.149 - An Introduction to General, Organic, and Biological Chemistry

Question

Identify the group number in the periodic table of $X$ , a representative element, in each of the following ionic compounds: $(6.2)$

a. $XC{l}_3$

b. $A{l}_2{X}_3$

c. $XC{O}_3$

Step-by-Step Solution

Answer

a. The group number is $3A\left(13\right)$.

b. The group number is $6A\left(16\right)$.

c. The group number is $2A\left(2\right)$.

Part (a) step 1: Given Information

We need to identify the group number of $XC{l}_3$.

Part (a) step 2: Simplify

Consider: $XC{l}_3$

ion of Chlorine $C{l}^{-}$ change of $X$ is $x$ so by change balance:

$$\begin{gathered} x+3(1-)=0 \\ x=3+ \end{gathered}$$

Therefore, ion of $x‐‐‐X^{3+}$

Here, three electrons donated to achieve octect so group is $3A\left(13\right)$.

Part (b) step 1: Given Information

We need to identify the group number of $A{l}_2{X}_3$.

Part (b) step 2: Simplify

Consider: $A{l}_2{X}_3$

ion of  Aluminium $A{l}^{3+}$ change of $X$is $x$ so by change balance:

$$\begin{gathered} 3x+2(3+)=0 \\ x=2- \end{gathered}$$

Therefore ion of $x‐‐‐X^{2-}$

Here, two electrons accepted to achieve octect so the group is $6A\left(16\right)$.

Part (c) step 1: Given Information

We need to identify the group number of $XC{O}_3$.

Part (c) step 2: Simplify

Consider: $XC{O}_3$

ios of Carbonate ${CO}_3^{2-}$ charge of $X$ is $x$ so by charge balance:

$$\begin{gathered} x+\left(2-\right)=0 \\ x=2+ \end{gathered}$$

Therefore, ion of $x‐‐‐X^{2+}$

Here, two electrons donated to achieve octect so group is $2A\left(2\right)$.