Q. 6.112

Consider an ion with the symbol $Y^{3 -}$ formed from a representative element.

a. What is the group number of the element?

b. What is the Lewis symbol of the element?

c. If $Y$ is in Period $3$ , what is the element?

d. What is the formula of the compound formed from $Y$ and

the barium ion?

Verified

Answer

a. Group number of the element will be $15$ ,

b. Lewis symbol is given below.

c. The element will be phosphide.

d. The formula of the compound formed from $Y$ and barium ion is $B a_{3} Y_{2}$ .

1Part(a) Step 1: Given information

We need to find the group number of respective element.

2Part(a) Step 2: Explanation

As the element lacks three electrons in outermost shell to achieve noble gas configuration so the group number will be $15$ .

3Part(b) Step 1: Given information

We need to find the Lewis symbol for the given element.

4Part(b) Step 2: Explanation

As it has achieved noble gas configuration so it has $8$ electrons in outermost shell so the Lewis symbol will be

5Part(c) Step 1: Given information

We need to find the element with period number $3$ and group number $15$ .

6Part(c) Step 2: Explanation

The element with group number $15$ and period $3$ is magnesium with symbol $P^{3 -}$ .

7Part(d) Step 1: Given information

We need to find the formula of the compound formed between $Y$ and Barium.

8Part(d) Step 2: Explanation

Oxidation state of $Y$ is $3 -$ .

Oxidation state of Barium is $+ 2$ .

So the formula of compound will be $B a_{3} Y_{2_{}}$ .