Q. 6.110

Question

Tipping. In the article "Are Christian/Religious Pcople Poor Tippers?" (hournol of A,piled Sockal Psychology, Vol. 43. Issue 5 . pp. 928-935), M. Lynn and B. Katz report that, for customers who receive bad service, the mean percentage tip is 8.56%of the bill with a standard deviation of 5.37%. Let x represent the percentage of the bill that a customer tips when he or she receives bad service.

a. What percentage of tips for bad service are at least 0 se?

b. Assuming that x is aprroximalely noemally distribuled, uve normalcurve areas to determine the approximate percentage of tips for bad service that are at least 0%

c. Based on your results from parts (a) and (b), do you think that the percentage of the bill that a customer tips when he or she receives bad service is appeexinately a normally distributed variable? Explain your answer.

Step-by-Step Solution

Verified
Answer

a)100%

b)94.41%

c)No

1Part (a)Step 1: Given Information

To determine the fraction of bad service tips that are at least 0%

2Part(a)Explanation : Step 1

The bill's percentage tip to the unsatisfactory service The mean of (x)isμ=8.56%and the standard deviation isσ=5.37%

Negative suggestions are not possible based on the facts provided. As a result, bad-service tips are always more than or equal to 0%. As a result, the probability of receiving a tip for poor service is at least 0% is 100%

3Part(b) Given Information: Step 1

To discover the percentage of tips for terrible service that are at least 0% if X is roughly followed by a normal distribution.

4Part(b) Explanation :Step 2

The random variable x's z-score is calculated as follows:

z=x-μσ

Calculate the z - scores:


z=0-8.565.37  -1.59

Using the normal probability table in Appendix A, calculate the corresponding probability:

P(x>0)=P(z>-1.59)

              =1-0.0559

              =94.41%

5Part(c) Given Information : Step 1

To determine whether x follows a normal distribution roughly based on the results of parts (a) and (b) (b).

6Part(b) Explanation : Step 2

The percentages in parts (a) and (b) above should be equal to 100%, yet the outcomes of part (a) and (b) differ significantly (b). As a result, it is impossible to establish that x follows a normal distribution.