Q 6.102

Question

For the function f(x)=6x2 +13x-15, find

(a) the zeros of the function

(b) any x-intercepts of the graph of the function

(c) any y-intercepts of the graph of the function.

Step-by-Step Solution

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Answer

Part a. The zeros of the function are 56, -3.

Part b. The x-intercepts of the graph of the functions are (56,0) and (-3,0).

Part c. The y-intercept of the graph of the function is (0,-15).

1Part a Step 1. Given Information

The given function is f(x)=6x2+13x-15.

We have to find the zeros of the function.

2Part a Step 2. Finding the zeros of the function

To find the zeros of the function, substitute 0 for f(x).

So, f(x)=6x2+13x-150=6x2+13x-15

Now, by factoring the trinomial we get

0=(6x-5)(x+3)

Therefore, the zeros of the function are

 6x-5=0x=56 and x+3=0x=-3

3Part b Step 1. Given Information

The given function is f(x)=6x2+13x-15.

We have to find any x-intercepts of the graph of the function.

4Part b Step 2. Finding x-intercepts of the graph of the function

The x-intercept occurs when y=0

As we depict that the zeros of the function are x=56,-3

Therefore, f(56)=0f(-3)=0

Thus, the points (56,0) and (-3,0) lie on the graph and these points are the x-intercepts of the function.

5Part c Step 1. Given Information

The given function is f(x)=6x2+13x-15.

We have to find the y-intercepts of the graph of the function. 

6Part c Step 2. Finding y-intercepts of the graph of the function

The y-intercept occurs when x=0

So, substitute 0 for x in f(x)

f(0)=6(0)2+13(0)-15f(0)=0+0-15f(0)=-15

Thus, the point (0, -15) lies on the graph and this point is the y-intercept of the function.