Q. 6

Question

Suppose fx=2x-4,gx=x-2. Find the equations of the tangent lines to these functions at x=2. Then argue graphically that it would be reasonable to think that the limit of the quotient fxgx as x2 might be equal to the limit of the quotient of these tangent lines as x2.

Step-by-Step Solution

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Answer

y=2.8x-5.6 is the line tangent to fx when x is 2.

y=x-2 is the line tangent to gx when x is 2.

Very close to x=2 the graphs of f,g are very close to the graphs of the given tangent lines.

1Step 1. Given information.

Consider the given question,

fx=2x-4,gx=x-2

2Step 2. Consider the function f x .

Consider the function fx=2x-4.

The point of tangency is given below,

f2=22-4=0f22,0

Slope of tangent, f'x=ln 2·2x.

Then the slope of tangent at x=2,

f'2=ln 2·22=2.8

So y=mx+c.

Substitute the values in the above equation,

0=2.8×2+cc=-5.6y=2.8x-5.6

3Step 3. Consider the function g x .

Consider the function gx=x-2.

The point of tangency is given below,

f2=2-2=0f22,0

Slope of tangent, g'x=1.

Then the slope of tangent at x=2,

g'2=1

So y=mx+c.

Substitute the values in the above equation,

0=1×2+cc=-2y=x-2

4Step 4. Plot the graphs.

The two tangent lines are y=2.8x-5.6y=x-2.

On plotting the graph,



From the graph, we can say the limit of the quotient of tangent lines as x2is equal to the limit of the quotient fxgx as x2.