Q 5.76 - Intermediate Algebra

Question

Find the quotient $\left(-48a^8{b}^4-36a^6{b}^5\right)÷\left(-6a^3{b}^3\right)$

Step-by-Step Solution

Answer

The quotient is $2a^{3}b\left(4a^2+3b\right)$

Step 1. Given information

$\left(-48a^8{b}^4-36a^6{b}^5\right)÷\left(-6a^3{b}^3\right)$

Step 2. Divide the polynomial

Rewrite as fraction

$\frac{\left(-48a^8{b}^4-36a^6{b}^5\right)}{\left(-6a^3{b}^3\right)}$

Divide each term by the divisor

$\frac{-48a^8{b}^4}{-6a^3{b}^3}-\frac{36a^6{b}^5}{-6a^3{b}^3}$

Simplify

$2a^{3}b\left(4a^2+3b\right)$