Q. 57. - Calculus

Question

For the partial derivatives given in Exercises 55–58, find the

most general form for a function of three variables, $f(x,y,z)$,

with the given partial derivative.

$\frac{{\partial }^{2}f}{\partial x^2}=0$

Step-by-Step Solution

Answer

The most general form of a function $f(x, y, z)$so that $\frac{{\partial }^{2}f}{\partial x^2}=0$is $f(x,y,z)=x{h}_1(y,z)+h_2(y,z)$

Step 1: Given information

Given derivative is $\frac{{\partial }^{2}f}{\partial x^2}=0$

Step 2: The objective is to find the most general form of a function f ( x ,   y ,   z )  

The most general form of a function $f(x, y, z)$so that $\frac{{\partial }^{2}f}{\partial x^2}=0$

Suppose, $f(x,y,z)=x{h}_1(y,z)+h_2(y,z)$

Then,

$$\begin{gathered} \frac{df}{dx}=h_1(y,z)+0 \\ \frac{d^{2}f}{d{x}^2}=0 \end{gathered}$$

Hence, the most general form of $f$ so that $\frac{{\partial }^{2}f}{\partial x^2}=0$is $f(x,y,z)=x{h}_1(y,z)+h_2(y,z)$