Q. 56 - Intermediate Algebra

Question

In the following exercises, add the polynomials. 

$\left(2r^2-3rs-2s^2\right)+\left(5r^2-3rs\right)$

Step-by-Step Solution

Answer

Hence,

$\left(2r^2-3rs-2s^2\right)+\left(5r^2-3rs\right)=7r^2-6rs-2s^2$

Step 1. Given information

$\begin{array}{l}\text{The given expressions is}\\ \left(2r^2-3rs-2s^2\right)+\left(5r^2-3rs\right)\\ \text{We have to find the sum of the polynomials.}\end{array}$

Step 2. Add the polynomials

$\begin{array}{l}\Rightarrow \left(2r^2-3rs-2s^2\right)+\left(5r^2-3rs\right)\\ =2r^2-3rs-2s^2+5r^2-3rs\left[\text{Rewrite without parentheses}\right]\\ =2r^2+5r^2-3rs-3rs-2s^2\left[\text{Combine the like terms}\right]\\ =7r^2-6rs-2s^2\left[\text{Simplify}\right]\end{array}$