Q. 5.38 - An Introduction to General, Organic, and Biological Chemistry

Question

A vial contains radioactive iodine- $131$ with an activity of $20 \mathrm{mCl}/\mathrm{ml}$. If a thyroid test requires $3.0 \mathrm{mCi}$ in an "atomic cocktail." how many milliliters are used to prepare the iodine-$131$ solution?

Step-by-Step Solution

Answer

$1.5 mL$are used to prepare the iodine-$131$ solution.

Step 1: Given information

Iodine isotope that is radioactive and has an atomic mass of$131$, It has an eight-day half-life and may have anti-cancer capabilities. Iodine $131$, Thyroid cells are killed and thyroid hormone synthesis is reduced when this substance builds up in the thyroid gland and emits beta and gamma particles.

Step 2: Explanation

Conversion factor/equalities

$2.0\mathrm{mci} = 1\mathrm{ml}$

$\frac{2.0\mathrm{mci}}{1\mathrm{ml}} and \frac{1\mathrm{ml}}{2.0\mathrm{mci}}$

Step 2 Establish the issue

$3.0 ml \times \frac{1\mathrm{ml}}{2.0\mathrm{mci}} =1.5 ml$