Q. 53 - Algebra 2

Question

For exercises $\mathbf{53}-\mathbf{55},$ use the following information.

Suppose the temperature $T^o\left(C\right)$ below Earth’s surface is given by $T\left(d\right)=35d+20$, where $\mathbf{d}$ is the depth $\left(\mathbf{km}\right).$

Find the temperature at a depth of $\mathbf{2}$ kilometres.

Step-by-Step Solution

Answer

The temperature at a depth of 2 kilometres is ${90}^{o}C$.

Step 1. Given information

A linear equation $T\left(d\right)=35d+20$ and depth $\left(d\right)=2\left(km\right).$

Step 2. To find the temperature at depth of 2 (km)

Substitute the value of $d=2$ in the given equation.

Now,

 $\begin{array}{l}T\left(2\right)=35\times 2+20\\ \Rightarrow T\left(2\right)=70+20\\ \Rightarrow T\left(2\right)=90\end{array}$

Step 3. Conclusion

Therefore, the value of $T\left(d\right)$ is $90$ at the depth is 2 kilometers. $(2,70)$

Hence, the temperature at a depth of 2 kilometres is ${90}^{o}C$.