Q. 5 - Precalculus Enhanced with Graphing Utilities

Question

Find the following for each function:

$f\left(x\right)=\frac{x^2-4}{x^2}$

Part (a): $f\left(2\right)$

Part (b): $f\left(-2\right)$

Part (c): $f\left(-x\right)$

Part (d): $-f\left(x\right)$

Part (e): $f\left(x-2\right)$

Part (f): $f\left(2x\right)$

Step-by-Step Solution

Answer

Part (a): $f\left(2\right)=0$

Part (b): $f\left(-2\right)=0$

Part (c): $f\left(-x\right)=\frac{x^2-4}{x^2}$

Part (d): $-f\left(x\right)=\frac{-x^2+4}{x^2}$

Part (e): $f\left(x-2\right)=\frac{x\left(x-4\right)}{{\left(x-2\right)}^2}$

Part (f): $f\left(2x\right)=\frac{x^2-1}{x^2}$

Part (a) Step 1. Given information.

Consider the given function,

$f\left(x\right)=\frac{x^2-4}{x^2}$

Substitute $2$ in the given equation,

$$\begin{gathered} f\left(2\right)=\frac{{\left(2\right)}^2-4}{{\left(2\right)}^2} \\ f\left(2\right)=\frac{4-4}{4} \\ f\left(2\right)=0 \end{gathered}$$

Part (b) Step 1. Given information.

Consider the given function,

$f\left(x\right)=\frac{x^2-4}{x^2}$

Substitute $-2$ in the given equation,

$$\begin{gathered} f\left(-2\right)=\frac{{\left(-2\right)}^2-4}{{\left(-2\right)}^2} \\ f\left(-2\right)=\frac{4-4}{4} \\ f\left(-2\right)=0 \end{gathered}$$

Part (c) Step 1. Given information.

Consider the given function,

$f\left(x\right)=\frac{x^2-4}{x^2}$

Substitute $-x$ in the given equation,

$$\begin{gathered} f\left(-x\right)=\frac{{\left(-x\right)}^2-4}{{\left(-x\right)}^2} \\ f\left(-x\right)=\frac{x^2-4}{x^2} \end{gathered}$$

Part (d) Step 1. Given information.

Consider the given function,

$f\left(x\right)=\frac{x^2-4}{x^2}$

From the question,

$$\begin{gathered} -f\left(x\right)=-\left(\frac{x^2-4}{x^2}\right) \\ -f\left(x\right)=\frac{-x^2+4}{x^2} \end{gathered}$$

Part (e) Step 1. Given information.

Consider the given function,

$f\left(x\right)=\frac{x^2-4}{x^2}$

Substitute $x-2$ in the given equation,

$$\begin{gathered} f\left(x-2\right)=\frac{{\left(x-2\right)}^2-4}{{\left(x-2\right)}^2} \\ f\left(x-2\right)=\frac{x^2+4-4x-4}{{\left(x-2\right)}^2} \\ f\left(x-2\right)=\frac{x^2-4x}{{\left(x-2\right)}^2} \\ f\left(x-2\right)=\frac{x\left(x-4\right)}{{\left(x-2\right)}^2} \end{gathered}$$

Part (f) Step 1. Given information.

Consider the given function,

$f\left(x\right)=\frac{x^2-4}{x^2}$

Substitute $2x$ in the given equation,

$$\begin{gathered} f\left(2x\right)=\frac{{\left(2x\right)}^2-4}{{\left(2x\right)}^2} \\ f\left(2x\right)=\frac{4x^2-4}{4x^2} \\ f\left(2x\right)=\frac{4\left(x^2-1\right)}{4x^2} \\ f\left(2x\right)=\frac{x^2-1}{x^2} \end{gathered}$$