Q. 5

Question

Consider the series k=1(-1)k+1ak and k=1(-1)kakwhere (i) {ak} is a sequence of positive number (ii) the sequence {ak} is strictly decreasing (iii) limkak=0

 A series can fail two of the three conditions, (i), (ii) and (iii), and still converge. Which of the three conditions must an alternating series pass in order to converge? 

Step-by-Step Solution

Verified
Answer

According to the Divergence Test if the sequence {ak} does not converge to zero, then the


series  k=1ak, diverges.


Hence, for the series k=1(-1)k+1ak and k=1(-1)kak  , to be convergent it must pass the third condition.

1Step 1. Given

 Given the series k=1(-1)k+1ak and k=1(-1)kakwhere (i) {ak} is a sequence of positive number (ii) the sequence {ak} is strictly decreasing (iii) limkak=0

2Step 2. Explanation

If the third condition is not passed by an alternating series , then limkak=0.

According to the Divergence Test if the sequence {ak} does not converge to zero, then the


series k=1ak, diverges.


Hence, for the series k=1(-1)k+1ak and k=1(-1)kak , to be convergent it must pass the third condition.