Q. 49 - Calculus

Question

Use tables of values to make educated guesses for each of the limits in Exercises 39–52. 

$\underset{x\to \infty }{\lim }\frac{x+1}{x^2-1}$

Step-by-Step Solution

Answer

The value is $0.$

Step 1. Given information.

The given function is $\underset{x\to \infty }{\lim }\frac{x+1}{x^2-1}$.

Step 2. Value of the limit.

Consider the table,

The value approaches to zero as $x\to \infty$

Therefore,

$\underset{x\to \infty }{\lim }\frac{x+1}{x^2-1}=0$