Q 48. - Precalculus Enhanced with Graphing Utilities

Question

In Problems 45–52, show that $(f\circ g)\left(x\right)=(g\circ f)\left(x\right)=x$

$f\left(x\right)=x+5; g\left(x\right)=x-5$

Step-by-Step Solution

Answer

$$\begin{gathered} (f\circ g)\left(x\right)=x \\ (g\circ f)\left(x\right)=x \end{gathered}$$

Therefore, $(f\circ g)\left(x\right)=(g\circ f)\left(x\right)=x$

Step 1. Given information.

The given composite function is:

$$\begin{gathered} f\left(x\right)=x+5 \\ g\left(x\right)=x-5 \end{gathered}$$

When we are given two functions f and g, the composite function which is denoted by $f\circ g$ is defined by $(f\circ g)\left(x\right)=f\left(g\right(x\left)\right)$.

Step 2. Find ( f ∘ g ) ( x ) .

$(f\circ g)\left(x\right)=f\left(g\right(x\left)\right)$

Now substitute $g\left(x\right)=x-5$ in the function $f\left(g\right(x\left)\right)$,

Then the function will become $f(x-5)$,

$$\begin{gathered} f(x-5)=x-5+5 \\ =x \end{gathered}$$

Therefore, $(f\circ g)\left(x\right)=x$.

Step 3. Find ( g ∘ f ) ( x ) .

$(g\circ f)\left(x\right)=g\left(f\right(x\left)\right)$

Substitute $f\left(x\right)=x+5$ in the function $g\left(f\right(x\left)\right)$

$$\begin{gathered} (g\circ f)\left(x\right)=g\left(f\right(x\left)\right) \\ =g(x+5) \\ =x+5-5 \\ =x \end{gathered}$$

Therefore,$(g\circ f)\left(x\right)=x$.

It is shown that $(f\circ g)\left(x\right)=(g\circ f)\left(x\right)=x$.