Q. 48 - Calculus

Question

$\underset{x\to +2}{\lim }\sqrt{2^x-4}$

Step-by-Step Solution

Answer

$\underset{x\to +2}{\lim }\sqrt{2^x-4}=0$

Step 1. Given information

$\underset{x\to +2}{\lim }\sqrt{2^x-4}$

Step 2. Plug in the values

$\underset{x\to +2}{\lim }\sqrt{2^x-4}=\sqrt{2^2-4}$

$\underset{x\to +2}{\lim }\sqrt{2^x-4}=\sqrt{4-4}$

$\underset{x\to +2}{\lim }\sqrt{2^x-4}=0$