Q. 47 - Calculus

Question

Integral Formulas: Fill in the blanks to complete each of the

following integration formulas.

(The last six formulas involve hyperbolic functions and their inverses.)
$\int \frac{1}{\sqrt{x^2+1}}dx=\_\_\_\_$

Step-by-Step Solution

Answer

$\int \frac{1}{\sqrt{x^2+1}}dx=\ln \left|\sqrt{x^2+1}+x\right|+C$

Step 1. Given Information

$\int \frac{1}{\sqrt{x^2+1}}dx=\_\_\_\_$

Step 2. Solving the expression

From the formula of integration
$\int \frac{1}{\sqrt{x^2+1}}dx=\ln \left|\sqrt{x^2+1}+x\right|+C$

Where $C$ is constant.

So,
$\int \frac{1}{\sqrt{x^2+1}}dx=\ln \left|\sqrt{x^2+1}+x\right|+C$