Q. 47

Question

In Problems 35–58, graph each function. Be sure to label key points and show at least two cycles. Use the graph to determine the domain and the range of each function.   

y=2sinx+3

Step-by-Step Solution

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Answer

The graph of the function is:  


The domain is: -,

The range is:1,5

1Step 1. Given information

The function to be plotted is :

y=2sinx+3

2Step 2. Determine the amplitude and period of y = 2 sin x .

By comparing the given function y=2sinx with y=Asinωx

we get amplitude: A=2

Time period : T=2πωT=2π1T=2π

The graph of y=2sinx will lie  between -2 and 2 on the y-axis. One cycle begins at  x=0 and ends at x=2π.

3Step 3. : Divide the interval into four subintervals of the same length

Divide the interval 0,2π into four subintervals,

each of length:2π4=π2

 The x-coordinates of the five key points are :

First x-coordinate is 0

second x-coordinate is 0+π2=π2

Third x-coordinate is π2+π2=π

Fourth x-coordinate is π+π2=3π2

Fifth x-coordinate is 3π2+π2=2π

These values represent the x-coordinates of the five key points on the graph. 

4Step 4. Use the endpoints of these subintervals to obtain five key points on the graph.

Since y=2sinx

 multiply the y-coordinates of the five key points for y=sinxby 2.

 The five key points on the graph of y=2sinx are :

0,0,π2,2,π,0,3π2,-2,2π,0.

Add 3 to this y-coordinate of key points to get key points for the function: y=2sinx+3.

So five key points of the given function are:

0,3,π2,5,π,3,3π2,1,2π,3

5Step 5. Plot the five key points and draw a sinusoidal graph to obtain the graph of one cycle. Extend the graph in each direction to make it complete.

Plot the five key points obtained in Step 4 and fill in the graph . Extend the graph in each direction to obtain the complete graph . Notice that additional key points appear every π2  radian.  



6Step 6. To find domain and range of the function

As we can see that the value of xis set of all real numbers.

So domain is -,.

The y- value of the function in the graph lies from 1 to 5.

So the range of the function is 1,5.