Q. 46 - Calculus

Question

Use tables of values to make educated guesses for each of the limits in Exercises 39–52. 

$\underset{x\to \infty }{\lim }\left(3e^{-2x}+1\right)$

Step-by-Step Solution

Answer

The value is $1.$

Step 1. Given information.

The given function is $\underset{x\to \infty }{\lim }\left(3e^{-2x}+1\right).$

Step 2. Value of the limit.

The table is,

The value approaches to $1$ as$x$ increases,

Therefore,

$\underset{x\to \infty }{\lim }\left(3e^{-2x}+1\right)=1$.