Q. 4.50

Question

Write the electron arrangement for each of the following
elements: (Example: sodium 2,8,1)
a. Phosphorus
b. Neon 
c. Sulfur

d. Magnesium

e. Aluminum 
f. Fluorine 

Step-by-Step Solution

Verified
Answer

Electron arrangement of elements are:

(a) Phosphorus (2, 8, 5)
(b) Neon (2, 8)
(c) Sulfur (2, 8, 6)

(d) Magnesium (2, 8, 2)

(e) Aluminum (2, 8, 3)
(f) Fluorine (2, 7)

1Part (a) Step 1: Given information

We need to find electron arrangement for phosphorus.

2Part (a) Step 2: Explanation

Atomic number phosphorus = 15

Symbol = P

Electron arrangement = 2,8 , 5

Hence, electron arrangement of phosphorus is 2, 8, 5 

3Part (b) Step 1: Given information

We need to find electron arrangement for neon.

4Part (b) Step 2: Explanation

Atomic number neon = 10

Symbol = Ne

Electron arrangement = 2, 8 

Hence, electron arrangement of neon is 2, 8

5Part (c) Step 1: Given information

We need to find electron arrangement for sulfur.

6Part (c) Step 2: Explanation

Atomic number sulfur = 16

Symbol = S

Electron arrangement = 2, 8, 6

Hence, electron arrangement of sulfur is 2, 8, 6.

7Part (d) Step 1: Given information

We need to find electron arrangement for magnesium.

8Part (d) Step 2: Explanation

Atomic number magnesium = 12

Symbol = Mg

Electron arrangement = 2, 8, 2

Hence, electron arrangement of magnesium is 2, 8, 2.

9Part (e) Step 1: Given information

We need to find electron arrangement for aluminum.

10Part (e) Step 2: Explanation

Atomic number aluminum = 13

Symbol = Al

Electron arrangement = 2, 8, 3

Hence, electron arrangement of aluminum is 2, 8, 3

11Part (f) Step 1: Given information

We need to find electron arrangement for fluorine.

12Part (f) Step 2: Explanation

Atomic number fluorine = 9

Symbol = F

Electron arrangement = 2, 7

Hence, electron arrangement of fluorine is 2, 7