Q. 450 - Intermediate Algebra

Question

Factor completely:

$40r^2+810$.

Step-by-Step Solution

Answer

The factored polynomial is,

$10(4r^2+81)$.

Step 1. Given the information.

The polynomial function is,

$40r^2+810$.

Step 2. Factoring the polynomial.

$40r^2+810$

Taking out the common factor,

$=10(4r^2+81)$.

Step 3. Checking the solution

$10(4r^2+81)$

Multiplying the brackets,

$$\begin{gathered} =10\times 4r^2+10\times 81 \\ =40r^2+810 \end{gathered}$$

This is true.