Q. 445 - Intermediate Algebra

Question

Factor completely:

$80a^2+120a^3$.

Step-by-Step Solution

Answer

The factored polynomial is:

$40a^2(2+3a)$

Step 1. Given the information.

The polynomial function is,

$80a^2+120a^3$

Step 2. Factoring the polynomial.

$80a^2+120a^3$

Taking the common factors,

$=40a^2(2+3a)$

Step 3. Checking the solution

$40a^2(2+3a)$

Multiplying the brackets,

$$\begin{gathered} =40a^2\times 2+40a^2\times 3a \\ =80a^2+120a^3 \end{gathered}$$

This is true.