Q. 4.32
Question
Road Grade. The grade of a road is defined as the distance it rises (or falls) to the distance it runs horizontally, usually expressed as a percentage. Consider a road with a positive grade, . Suppose that you begin driving on that road at an altitude
a. Find the linear equation that expresses the altitude, , when you have driven a distance, , along the road. (Hint: Draw a graph and apply the Pythagorean Theorem
b. Identify and interpret the -intercept and slope of the linear equation in part (a).
c. Apply your results in parts (a) and (b) to a road with a grade and an initial altitude of . Express your answer for the slope to four decimal places.
d. For the road in part (c). what altitude will you reach after driving along the road?
e. For the road in part (c), how far along the road must you drive to reach an altitude of ?
Step-by-Step Solution
Verified(a) The required linear equation is,
(b) The -intercept is, and the slope is,
(c) The required answer is,
(d) The required altitude is,
(e) The distance to be driven is,
We are given that,
The road has a positive grade,
And we begin driving at an altitude of
We need to indicate altitude after driving distance on the road.
Grade represents a fraction of the height of each unit. When we drive a distance of , the height thus rises by .
However, the first height is so the total height after the rise is .
Hence the equation is,
Here, is the altitude after covering some distance
We need to find out the -intercept and slope of the equation.
From part (a)
The -intercept is the constant in the equation i.e.
And the slope is the coefficient of , i.e.,
We need to find the value of altitude i.e.
As the values are,
So, from part (a) and above values we get,
We need to find the value at a distance and other conditions same as that of part (c)
From part (c) we get
Hence the reached altitude is,
We need to find the distance drove.
From part (c)
As
So,
Therefore, distance drove is